0=x^2-168x+6400

Solution for 0=x^2-168x+6400 equation:

0=x^2-168x+6400

We move all terms to the left:

0-(x^2-168x+6400)=0

We add all the numbers together, and all the variables

-(x^2-168x+6400)=0

We get rid of parentheses

-x^2+168x-6400=0

We add all the numbers together, and all the variables

-1x^2+168x-6400=0

a = -1; b = 168; c = -6400;
Δ = b2-4ac
Δ = 1682-4·(-1)·(-6400)
Δ = 2624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2624}=\sqrt{64*41}=\sqrt{64}*\sqrt{41}=8\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(168)-8\sqrt{41}}{2*-1}=\frac{-168-8\sqrt{41}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(168)+8\sqrt{41}}{2*-1}=\frac{-168+8\sqrt{41}}{-2}
$